b^2+10b+12=3

Solution for b^2+10b+12=3 equation:

Simplifying
b2 + 10b + 12 = 3

Reorder the terms:
12 + 10b + b2 = 3

Solving
12 + 10b + b2 = 3

Solving for variable 'b'.

Reorder the terms:
12 + -3 + 10b + b2 = 3 + -3

Combine like terms: 12 + -3 = 9
9 + 10b + b2 = 3 + -3

Combine like terms: 3 + -3 = 0
9 + 10b + b2 = 0

Factor a trinomial.
(9 + b)(1 + b) = 0

Subproblem 1
Set the factor '(9 + b)' equal to zero and attempt to solve:

Simplifying
9 + b = 0

Solving
9 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + b = 0 + -9
b = 0 + -9

Combine like terms: 0 + -9 = -9
b = -9

Simplifying
b = -9
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {-9, -1}